6-2(2x^2+2)=x+17

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Solution for 6-2(2x^2+2)=x+17 equation: 



6-2(2x^2+2)=x+17

We move all terms to the left:

6-2(2x^2+2)-(x+17)=0

We multiply parentheses

-4x^2-(x+17)-4+6=0

We get rid of parentheses

-4x^2-x-17-4+6=0

We add all the numbers together, and all the variables

-4x^2-1x-15=0

a = -4; b = -1; c = -15;
Δ = b2-4ac
Δ = -12-4·(-4)·(-15)
Δ = -239
Delta is less than zero, so there is no solution for the equation

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